(9x)^2+(16x)^2=1024

Solution for (9x)^2+(16x)^2=1024 equation:

(9x)^2+(16x)^2=1024

We move all terms to the left:

(9x)^2+(16x)^2-(1024)=0

We add all the numbers together, and all the variables

25x^2-1024=0

a = 25; b = 0; c = -1024;
Δ = b2-4ac
Δ = 02-4·25·(-1024)
Δ = 102400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{102400}=320$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-320}{2*25}=\frac{-320}{50}
=-6+2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+320}{2*25}=\frac{320}{50}
=6+2/5
$